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December 18, 2014

December 18, 2014

Posted by **Kim** on Sunday, April 29, 2012 at 8:09pm.

- Probability and Statistics -
**Anonymous**, Sunday, April 29, 2012 at 10:35pm68%!

- Probability and Statistics -
**PsyDAG**, Monday, April 30, 2012 at 12:01pmHere is the method.

Z = (score-mean)/SEm

SEm = SD/√n

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to the Z scores.

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