The magnitude of an earthquake on the Richter scale is given by the formula R=log I, where I is the number of times more intense the quake is than the smallest measurable activity. How many times more intense i an earthquake having a richter scale number of 3.7 than the smallest measurable activity?
10^3.7 = 5012
To find out how many times more intense an earthquake is than the smallest measurable activity, given its Richter scale number of 3.7, we can use the formula R = log I, where R is the Richter scale number and I is the intensity factor.
Let's solve the equation:
R = log I
Given R = 3.7, we can plug it into the equation:
3.7 = log I
To get rid of the logarithm, we need to convert the equation into exponential form. The logarithm with base 10 can be rewritten using the exponentiation with base 10:
10^(3.7) = I
Evaluating the value of 10^(3.7), we find:
10^(3.7) ≈ 5011.8723
So, the intensity factor (I) for the earthquake with a Richter scale number of 3.7 is approximately 5011.8723 times more intense than the smallest measurable activity.