Posted by **john** on Sunday, April 29, 2012 at 5:50pm.

thank you so much help with the problem. i have trouble solving part b of the problem you helped me with. it told me to give it as a percentage, I got 10% but it is wrong. can you please help me

Superman must stop a 190-km/h train in 180m to keep it from hitting a stalled car on the tracks.

part a)If the train's mass is 3.8×10^5kg , how much force must he exert (find the magnitude)?

part b)Compare to the weight of the train (give as %).

partc) How much force(in magnitude) does the train exert on Superman?

college physics - Elena, Sunday, April 29, 2012 at 5:09pm

(a) v=190 km/h =52.8 m/s,

a =v^2/2•s =(52.8)^2/2•180 = 7.74 m/s^2,

F = m•a = 3.8•10^5•7.74 = 2.94•10^6 N.

(b) Weight = mg = 3.8•10^5•9.8= 3.76•10^6 N.

(c) F12 = -F21 = >

F = 2.94•10^6 N.

- @elena -
**john**, Sunday, April 29, 2012 at 5:55pm
nvm, i did it wrong. i already got the answer its 79% thanks

- @elena -
**Elena**, Sunday, April 29, 2012 at 5:57pm
2.94•10^6 ....100%,

3.76•10^6 ..... x %

x=(3.76•10^6 /2.94•10^6)•100% =127.9%

- @elena -
**Elena**, Sunday, April 29, 2012 at 6:02pm
3.76•10^6 ....100%,

2.94•10^6 ..... x %

x=(2.94•10^6 /3.76•10^6)•100% =78%

It depends on what to take for the base for comparison

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