how can concentration of Cl- in mixture of two chlorides be calculated given concentration of the chlorides
To calculate the concentration of Cl- in a mixture of two chlorides, you need to know the individual concentrations of the two chlorides and their respective valence or stoichiometric coefficients.
Let's assume the two chlorides are chloride A (concentration = [A]) and chloride B (concentration = [B]). Both chlorides dissociate in water, forming Cl- ions.
First, you need to determine the moles of Cl- contributed by each chloride. Since Cl- is the only anion in both chlorides, it contributes entirely to the concentration of Cl-. The moles of Cl- contributed by chloride A can be calculated using the concentration of A and its stoichiometric coefficient, while the moles of Cl- contributed by chloride B can be calculated using the concentration of B and its stoichiometric coefficient.
Next, add up the moles of Cl- from each chloride to obtain the total moles of Cl- in the mixture. Divide this total moles of Cl- by the volume of the solution to get the concentration of Cl-.
Here's the equation to calculate the concentration of Cl- in the mixture:
[Cl-] = ([A] * nA + [B] * nB) / (V)
Where:
[Cl-] = Concentration of Cl- in the mixture
[A] = Concentration of chloride A
[B] = Concentration of chloride B
nA = Stoichiometric coefficient of chloride A (number of Cl- ions contributed by each molecule of chloride A)
nB = Stoichiometric coefficient of chloride B (number of Cl- ions contributed by each molecule of chloride B)
V = Volume of the mixture
By plugging in the values for [A], [B], nA, nB, and V, you can calculate the concentration of Cl- in the mixture of the two chlorides.