Posted by Hannah on Sunday, April 29, 2012 at 3:56pm.
Yes, k1 for carbonic acid.
0.0885 - x = 4.2e-7
Then I added 0.0885 to the right side and got 8.85e-2. Would this be the concentration or do I need to do another step?
You need another step.
H2CO3 --> H^+ + HCO3^-
.0885-x...x......x
k1 = (H^+)(HCO3^-)/(H2CO3)
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