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April 19, 2014

Homework Help: Chemistry(Please respond)

Posted by Hannah on Sunday, April 29, 2012 at 2:58pm.

A 23.9 mL sample of 0.283 M trimethylamine, (CH3)3N, is titrated with 0.207 M hydrochloric acid.

At the equivalence point, the pH is?

I started off by doing

0.283 X 2.39e-2 = 6.76e-3

Then I did 6.76e-3 / 0.207 = 3.36e-2
2.39e-2 + 3.36e-2 = 5.65e-2

6.76e-3/5.65e-2 = 0.119

I do not know where to got from here. Thank you for your help!

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