Sunday

April 20, 2014

April 20, 2014

Posted by **Ashley** on Sunday, April 29, 2012 at 2:38pm.

- Honors Trig. -
**bobpursley**, Sunday, April 29, 2012 at 2:49pmHere is an easy way to do these.

1) convert all angles to 000N,090E, 180S, 270W

Example: 456@29deg S of E.

= 456@119

then convert to N, E coordinates.

V= 456(Cos119 N + Sin119 E)

Now for your problem:

V= 550(cos295 N +sin295 E)+28(cos109 N+ sin109)

combine N, E vector components:

V= N(550cos295+28cos109)+E(550sin295+28sin109)

do that math and you will have something like this

V= nnnn N + eeeee E

magnitude V= sqrt(nnnn^2+eeee^2)

direction= arctan (eeee/nnnn)

on the angle, be careful, as tangent is a repeating angle, it repeats each 180. So you may have to figure which quadrant.

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