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October 23, 2014

Homework Help: Chemistry

Posted by Mima on Sunday, April 29, 2012 at 1:20pm.

Calculate the cell potential for the following reaction as written at 79C given that [Zn^+2] = 0.819 M and [Ni^+2] = 0.014 M.
Zn + Ni^+2 = Zn^+2 + Ni

I know: E=E -RT/nF ln Q
reduction potential for Ni= -0.26
reduction potential for Zn = -0.76
so E standard potential = 0.5
E= 0.5 - (8.315)(352)/(2)(96480) ln 0.819/0.014.

I'm getting E= 1.989 and my answer is wrong.

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