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December 22, 2014

December 22, 2014

Posted by **david** on Sunday, April 29, 2012 at 10:18am.

- algebra -
**Reiny**, Sunday, April 29, 2012 at 10:40amlooks like your hyperbola has a vertical major axis

where a=1 and c=2

a^2 + b^2 = c^2

1 + b^2 = 4

b^2 = 3

how about

x^2 - (y^2)/3 = -1

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