balnce this equation, and show work
Crl3 + KOH + Cl2--> K2Cr2O7 + KIO4 + KCL + H2O
Cr changes from +3 to +6
I changes from -1 to +5
Cl changes from zero to -1
To balance the given chemical equation, we need to ensure that the number of atoms on both sides of the equation is equal. Let's break down the equation and balance it step by step:
Step 1: Balance the chromium (Cr) atoms:
There is one chromium atom on the left side and two on the right side. To balance this, multiply Crl3 by 2 on the left side:
2Crl3 + KOH + Cl2 --> K2Cr2O7 + KIO4 + KCL + H2O
Step 2: Balance the chlorine (Cl) atoms:
There are three chlorine atoms on the left side and one on the right side. To balance this, multiply KCl by 3 on the right side:
2Crl3 + KOH + Cl2 --> K2Cr2O7 + KIO4 + 3KCl + H2O
Step 3: Balance the potassium (K) atoms:
There is one potassium atom on the left side and six on the right side. To balance this, multiply KOH by 6 on the left side and K2Cr2O7 by 6 on the right side:
2Crl3 + 6KOH + Cl2 --> 6K2Cr2O7 + KIO4 + 3KCl + H2O
Step 4: Balance the iodine (I) atoms:
There is one iodine atom on the right side, so we need to balance it by multiplying KIO4 by 3 on the right side:
2Crl3 + 6KOH + Cl2 --> 6K2Cr2O7 + 3KIO4 + 3KCl + H2O
Now the equation is balanced with equal numbers of atoms on both sides.