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April 16, 2014

April 16, 2014

Posted by **ShelbyA** on Sunday, April 29, 2012 at 7:59am.

Max area which she can enclose with 60ft of fence in sq.ft?

dimensions to give area is 30ft by___ft?

- Algebra -
**Damon**, Sunday, April 29, 2012 at 8:06am2 w + L = 60 so L =60-2w

A = w L

A = w (60-2w)

A = -2w^2+60 w

2 w^2 -60 w = -A

w^2 - 30 w = -A/2

w^2 - 30 w + 225 = -A/2 + 450/2

(w-15)^2 =-(1/2)(A-450)

w = 15

L = 60-30 = 30

A = 450

- Algebra -
**Damon**, Sunday, April 29, 2012 at 9:06amIf you know any calculus, you can do this much faster

A = -2w^2+60 w

dA/dw = 0 at extreme = -4 w + 60

so w = 60/4 = 15 at max

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