Algebra 2
posted by Kelsey .
If an object is thrown vertically upward with an initial velocity of v, from an original position of s, the height h at any time t is given by: h=16t^2+vt+s(where h and s are in ft, t is in seconds and v is in ft/sec)
A package is thrown downward with an initial velocity of 5 ft/sec from a helicopter at 300 ft. A) what is the height of the package in 2 sec? B) how long does it take to hit the ground?
Round answer to 2 decimals Enter: blank ft,blank sec.

A. h = ho  (Vo*t + 16t^2).
h = 300  (5*2 + 16*2^2 )= 226 Ft above
gnd.
B. h = 300  (5t + 16t^2 = 0.
300  5t 16t^2 = 0.
16t^2  5t + 300 = 0.
Use Quad. Formula>
t = 4.18 s.