Posted by **Stella** on Saturday, April 28, 2012 at 11:20pm.

Two baseballs, each with a mass of 0.157 kg, are separated by a distance of 379 m in outer space, far from any other objects. If the balls are released from rest, what speed do they have when their separation has decreased to 173 m? Ignore the gravitational effects from any other objects.

What would the speed be, if the mass of the balls is quadrupled?

I tried using the equation v^2 = G M ((1 / R2) - (1 / R1)) and got the answer 2.07x10^-7 m/s, but the homework says that the answer is wrong.

- Physics -
**Elena**, Sunday, April 29, 2012 at 9:15am
PE2-PE1 = 2KE

G•m^2/r^2 - G•m^2/R^2 = 2•m•v^2/2.

v=sqrt[G•m•(R^2 - r^2)]/r•R =

= 1.66•10^-8 m/s

- Physics -
**Stella**, Monday, April 30, 2012 at 9:51am
Its wrong.

- Physics -
**Stella**, Monday, April 30, 2012 at 11:05am
v = sqrt(G*.157*((1/173) - (1/379))) = 1.81x10^-7 m/s

For the second question just multiply the mass by 4.

v= 3.63x10^-7 m/s

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