Posted by Darla on .
The equation of motion of a particle in vertical SHM is given by y = (10 cm) sin 0.80t.
(a) What is the particle's displacement at t = 1.1 s?
(b) What is the particle's velocity at t = 1.1 s?
(c) What is the particle's acceleration at t = 1.1 s?
remember !! 0.8 rad
y = 10•sin 0.8t = 10•sin 0.8•1.1 =7.7 cm
y`= 10•0.8•cos0.8•1.1 =5.1 cm/s,
y`` = 10• (0.8)^2• sin 0.8•1.1 =
= 4.9 cm/s^2