Posted by Sandy on .
Consider the following reaction:
H2(g) + I2(s) ---> 2HI(g)
TriangleH = 51.9 kj (enthalpy)
Calculate the standard enthalpies of reaction for the following reaction:
6HI(g) ---> 3H2(g) + 3I2(s)
You want the reverse of 3x the rxn.
That will be -51.9*3 kJ