Can someone look at my work and see what i did wrong. I did this 100 times but i keep getting it wrong
Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Then find the area of the region.
2y=3x^(1/2) , y=4 and 2y+1x=4
y=3(x^(1/2))/2, y=4 , y=2-(1/2)x
Intersection points = -4,1,64/9
Integral from -4 to 1
Integral from 1 to 64/9
please help i've been working on this for hours
Calculus: Area - Steve, Saturday, April 28, 2012 at 7:29pm
go to wolframalpha . com and enter
to see the curves involved.
The area of interest is a little v-shaped chunk from
(-4,4) down to (1,3/2) and back up to (64/9,4)
If you integrate on x, then the integrands use the limits you have, but
the height in each case is 4-y, for the appropriate f(x)
4 - (4-x)/2 from -4 to 1 = 25/4
4 - 3/2 sqrt(x) from 1 to 64/9 = 175/27
match anything you got?
Calculus: Area - jasmineT, Sunday, April 29, 2012 at 9:54pm
Thank you soooo much steve i finally got it right!!!! :D