Posted by Anonymous on Saturday, April 28, 2012 at 4:00am.
A 1.4mlong massless rod is pivoted at one end and swings around in a circle on a frictionless table. A block with a hole through the center can slide in and out along the rod. Initially, a small piece of wax holds the block 20 from the pivot. The block is spun at 50 , then the temperature of the rod is slowly increased. When the wax melts, the block slides out to the end of the rod. What is the final angular velocity?

physics  Elena, Saturday, April 28, 2012 at 4:25am
The moment of inertia (I) for the block (the point mass, as we are not given its dimensions) is mr^2:
I1 =m•r1^2 =m •0.2^2 =0.04•m,
I2 = m•r1^2 =m •1.4^2=1.96•m,
Acording to the law of conservation of angular momentum
L1 = L2
I1•ω1 = I2•ω2,
ω2 = I1•ω1/I2 =0.04•m•50/1.96•m =
=1.02 (units?)
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