Posted by **amir** on Saturday, April 28, 2012 at 3:28am.

in a reflection the image of the line y-2x=3 is the line 2y-x=9.find the axis of reflection.

- math grade 11 -
**MathMate**, Saturday, April 28, 2012 at 6:12am
The axis of reflection is the angle bisector of the two lines.

One of the properties of the axis of reflection is that any point lying on the line is equi-distant from both the original line and the image.

Distance of a point from a line Ax+By+C=0 is

±(Ax+By+C)/sqrt(A²+B²)

Can you take it from here?

- math grade 11 -
**Dany**, Wednesday, May 22, 2013 at 9:39am
YES

- math grade 11 -
**Samuel**, Sunday, December 15, 2013 at 2:45pm
Y=x+4

- math grade 11 -
**DawitGebeyaw**, Thursday, February 20, 2014 at 3:19pm
First find the intersection point of these lines and then also take one point from the line y = 2x 3 and calculate the distance from the intersection point to this point on the line. So this distance is equal to the distance fron the intersection point to the point (x,y) on the line 2y - x = 9. Then after by equiting them you can find (x,y). And so find the mid point between these two points. Finaly by using this mid point and the intersection point of these lines We can get the axis of reflection.

- BASSO PGSS @ D/BRHAN grade 11 -
**KIBEBEW GULILAT**, Thursday, June 4, 2015 at 8:51am
Y=0.988X+4.012 APPROXIMATLY Y=X+4

- math grade 11 -
**Anonymous**, Sunday, June 7, 2015 at 11:34am
Explain This Answer?

- math grade 11 -
**mubaarak**, Wednesday, February 24, 2016 at 11:30am
Y=5X/6 + 25/6

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