Posted by **Turk** on Saturday, April 28, 2012 at 12:35am.

If a projectile is launched vertically from the Earth with a speed equal to the escape speed, how far from the Earth's center is it when its speed is 1/9 of the escape speed?

- physics -
**Elena**, Saturday, April 28, 2012 at 7:59am
v=sqrt(2•G•M•R)

v1 = v/9 = sqrt(2•G•M•R)/9,

r =81•R = 81•6.4•10^6 m =5.18•10^8 m

- physics -
**Nick**, Saturday, April 11, 2015 at 12:48pm
5.16*10^8 for Mastering Physics

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