Posted by **Anonymous** on Friday, April 27, 2012 at 11:41pm.

Solve the trig equation exactly in the interval 0≤x≤2π.

tan x + tan π/3

------------------ = square root 3

1 - tan x tan π/3

- Solving Trig equation -
**Reiny**, Friday, April 27, 2012 at 11:56pm
you should recognize that they are using the formula

tan(A+B) = (tanA + tanB)/(1 - tanAtanB)

so

(tanx + tan π/3)/(1 - tanxtan(π/3) = √3

becomes

tan(x+π/3) = √3 ,

I know tan 60° or tan 240° = √3 OR tan π/3 or tan 4π/3 = √3

so x+π/3 = π/3 OR x+π/3 = 4π/3

x = 0 or x = π

but the period of tanx is π

so

x = 0 , π , 2π

## Answer This Question

## Related Questions

- Trig - Solve the trig equation exactly over the indicated interval. tanθ = ...
- Precalc/Trig - Sorry there are quite a few problems, but I just need to know if ...
- Trig - What is the total number of solutions for the equation 3 tan^2 A + tan A...
- Advanced Functions/Precalculus - Trigonometry Questions 1.) Find the exaqct ...
- Trigonometry - IM STUCK ON THESE :( 1. What is the equation for shifting the ...
- Trigonometry - IM STUCK ON THESE :( 1. What is the equation for shifting the ...
- Math - Write an equation of the tangent function with period (3π)/8, phase ...
- Advanced Functions/Precalculus - Trigonometry Questions 1. Solve the equation ...
- calculus - 1. what trig function has an amplitue of 1 and negative values for ...
- Calculus - How do I find the critical values? y= 4/x + tan(πx/8) What I ...

More Related Questions