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Posted by on Friday, April 27, 2012 at 10:30pm.

what mass of water at 10.0 degrees C is needed to cool 500.0ml of tea from 25.0 degrees C to 18.3 degrees C? Density and specific heat of the tea are the same as water.

  • chemistry - , Friday, April 27, 2012 at 11:03pm

    This is done the same way as adding cool water to warm water. The only difference is that you solve for mass cool water rather than Tfinal.

  • chemistry - , Saturday, April 28, 2012 at 11:05am

    (? x 4.184 x 6.7) = (500 x 4.184 x 8.3)
    28.03x = 17363.6
    x= 6.19 x 10(2)g

    is this correct?

  • chemistry - , Saturday, April 28, 2012 at 2:05pm

    I don't think so.
    It appears to me that you've reversed the delta T values.
    [? x 4.184 x (8.3)] = 500 x 4.184 x 6.7
    mass 10 C H2O needed approximately 400 g if I didn't punch the wrong keys.

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