what mass of water at 10.0 degrees C is needed to cool 500.0ml of tea from 25.0 degrees C to 18.3 degrees C? Density and specific heat of the tea are the same as water.
chemistry - DrBob222, Friday, April 27, 2012 at 11:03pm
This is done the same way as adding cool water to warm water. The only difference is that you solve for mass cool water rather than Tfinal.
chemistry - RoseBud, Saturday, April 28, 2012 at 11:05am
(? x 4.184 x 6.7) = (500 x 4.184 x 8.3)
28.03x = 17363.6
x= 6.19 x 10(2)g
is this correct?
chemistry - DrBob222, Saturday, April 28, 2012 at 2:05pm
I don't think so.
It appears to me that you've reversed the delta T values.
[? x 4.184 x (8.3)] = 500 x 4.184 x 6.7
mass 10 C H2O needed approximately 400 g if I didn't punch the wrong keys.