A 50.0kg cyclist on a 10.0kg bicycle speeds up from 5.0m/s to 10.0m/s , the total kinetic energy before acceleratingis 750, and after acceleratingis 3000, how much work is done to increase the kinetic energy of the cyclist and the bicycle
Work for changing KE of cyclist+bicycle is
W=Δ KE= KE2 –KE1=
=3000-750 = 2250 J,
for the cyclist:
W1=ΔKE1 = m1•v2^2/2 – m1•v1^2/2 =
=50•100/2-50•25/2 =1875 J,
for the bicycle:
W2=ΔKE2 = m2•v2^2/2 – m2•v1^2/2 =
=10•100/2 - 10•25/2 =375 J
I am 4 years in the future
I am 9 years in the future :) so cool
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We could also use:
50.0 10.0
i am 10 years in the future <3
To determine the work done to increase the kinetic energy of the cyclist and the bicycle, we need to calculate the change in kinetic energy. The change in kinetic energy is given by the formula:
ΔKE = KE_final - KE_initial
Where ΔKE is the change in kinetic energy, KE_final is the final kinetic energy, and KE_initial is the initial kinetic energy.
Given:
- Total mass of cyclist and bicycle (m_total) = mass of cyclist (m_cyclist) + mass of bicycle (m_bicycle) = 50.0 kg + 10.0 kg = 60.0 kg
- Initial velocity (v_initial) = 5.0 m/s
- Final velocity (v_final) = 10.0 m/s
- Initial kinetic energy (KE_initial) = 750 J
- Final kinetic energy (KE_final) = 3000 J
First, let's calculate the initial and final kinetic energies of the system:
KE_initial = 750 J
KE_final = 3000 J
Next, calculate the change in kinetic energy:
ΔKE = KE_final - KE_initial
ΔKE = 3000 J - 750 J
ΔKE = 2250 J
The change in kinetic energy represents the work done. Therefore, the work done to increase the kinetic energy of the cyclist and the bicycle is 2250 Joules.