Posted by **Tom** on Friday, April 27, 2012 at 8:14pm.

I just wanted to see if my answer if correct

the integral is:

∫(7x^3 + 2x - 3) / (x^2 + 2)

when I do a polynomial division I get:

∫ 7x ((-12x - 3)/(x^2 + 2)) dx

so then I use

u = x^2 + 2

du = 2x dx

1/2 du = x dx

= ∫7x - 12/2∫du/u - 3/1∫1/u

= (7x^2)/2 - 6/u - 3lnu + C

= (7x^2)/2 - 6/(x^2+2) - 3ln(x^2+2) + c

is my answer good?

Thanks

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