posted by Leonarda on .
Suppose that 50.0mL of 0.240M sulfric acid requires 36.0mL of KOH solution to reach its endpoint. What is the molarity of the KOH solution?
This works the same way as the Ba(OH)2 and HCl problem.
The equation is H2SO4 + 2KOH ==> K2SO4 = 2H2O