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March 30, 2017

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Write an equation in standard form for the hyperbola with center (0,0), vertex(4,0) , and focus (8,0).
1) x^2/64-x^2/16=1
2)x^2/16-y^2/64=1
3)y^2/48-x^2/16=1
4)x^2/16-y^2/48=1

  • algebra 2 - ,

    From the given information, you know that a = 4 and c = 8.

    Using b^2 = c^2 - a^2, we get this:

    b^2 = 8^2 - 4^2 = 64 - 16 = 48

    Substituting 16 for a^2 and 48 for b^2 gives us this in standard form:

    x^2/16 - y^2/48 = 1

    I hope this helps.

  • algebra 2 - ,

    Thank you again.

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