Posted by sam on Friday, April 27, 2012 at 1:56pm.
Write an equation in standard form for the hyperbola with center (0,0), vertex(4,0) , and focus (8,0).
1) x^2/64x^2/16=1
2)x^2/16y^2/64=1
3)y^2/48x^2/16=1
4)x^2/16y^2/48=1

algebra 2  MathGuru, Friday, April 27, 2012 at 7:49pm
From the given information, you know that a = 4 and c = 8.
Using b^2 = c^2  a^2, we get this:
b^2 = 8^2  4^2 = 64  16 = 48
Substituting 16 for a^2 and 48 for b^2 gives us this in standard form:
x^2/16  y^2/48 = 1
I hope this helps.

algebra 2  sam, Friday, April 27, 2012 at 9:11pm
Thank you again.
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