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December 18, 2014

December 18, 2014

Posted by **sam** on Friday, April 27, 2012 at 1:56pm.

1) x^2/64-x^2/16=1

2)x^2/16-y^2/64=1

3)y^2/48-x^2/16=1

4)x^2/16-y^2/48=1

- algebra 2 -
**MathGuru**, Friday, April 27, 2012 at 7:49pmFrom the given information, you know that a = 4 and c = 8.

Using b^2 = c^2 - a^2, we get this:

b^2 = 8^2 - 4^2 = 64 - 16 = 48

Substituting 16 for a^2 and 48 for b^2 gives us this in standard form:

x^2/16 - y^2/48 = 1

I hope this helps.

- algebra 2 -
**sam**, Friday, April 27, 2012 at 9:11pmThank you again.

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