Posted by **Nancy** on Friday, April 27, 2012 at 12:09pm.

If an object is thrown vertically upward with an initial velocity of v, from an original position of s, the height h at any time t is given by: h=-16t^2+vt+s (where h and s are in ft, t is in seconds and v is in ft/sec) Solve for t when the object hits the ground. (when h=0) t=blank 1 Âħsqrt blank 2-4(blank3)/2(-16) fill in the blanks of the quadratic formula. Enter blank 1, blank 2, blank 3

## Answer This Question

## Related Questions

- Algebra 2 - if an object is thrown vertically upward with an initial velocity of...
- Algebra 2 - If an object is thrown vertically upward with an initial velocity of...
- Algebra - If an object is thrown vertically upward with an initial velocity of ...
- Algebra 2 - If an object is thrown vertically upward with an initial velocity of...
- Algebra 2 - If an object is thrown vertically upward with an initial velocity of...
- Maath:) - If an object is thrown vertically upward with an initial velocity of v...
- Math - In physics, one learns that the height of an object thrown upward from an...
- Maths - object thrown upward from an initial height of h0 feet with an initial ...
- Algebra - THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the...
- Algebra - THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the...

More Related Questions