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March 31, 2015

March 31, 2015

Posted by **Latoya** on Friday, April 27, 2012 at 7:55am.

(please provide complete detailed answer)

- Statistics -
**MathGuru**, Friday, April 27, 2012 at 7:59pmUse a one-sample z-test.

z = (sample mean - population mean)/(standard deviation divided by the square root of the sample size)

With your data:

z = (43.5 - 40)/(8/√100) = ?

Finish the calculation.

Check a z-table at .05 level of significance for a one-tailed test.

If the z-test statistic exceeds the critical value from the z-table, reject the null. If the z-test statistic does not exceed the critical value from the z-table, do not reject the null.

I hope this will help get you started.

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