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February 1, 2015

February 1, 2015

Posted by **Connie** on Friday, April 27, 2012 at 4:28am.

Thanks

- Pre- Calculus -
**Reiny**, Friday, April 27, 2012 at 8:44amMake a sketch, I have 2 right-angled triangles

Let the point of observation be x ft from the building, let the height of the antenna be h ft

then

tan 62.2 =100/x

x = 100/tan62.2 = 52.724... (I stored in memory to keep accuracy)

In 2nd triangle

tan 65.8 = (h+100)/x

h+100 = xtan65.8

h = 52.724(tan65.8) - 100 = 17.32 ft

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