Post a New Question

Pre- Calculus

posted by .

An antenna is located at the top of a building 1000 ft tall. From a point on the same horizontal plane as the base of the building, the angles of elevation from the top and the bottom of the antenna are 65.8 degrees and 62.6 degrees respectively. How tall is the antenna.


  • Pre- Calculus -

    Make a sketch, I have 2 right-angled triangles
    Let the point of observation be x ft from the building, let the height of the antenna be h ft
    tan 62.2 =100/x
    x = 100/tan62.2 = 52.724... (I stored in memory to keep accuracy)

    In 2nd triangle
    tan 65.8 = (h+100)/x
    h+100 = xtan65.8
    h = 52.724(tan65.8) - 100 = 17.32 ft

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question