Saturday

April 18, 2015

April 18, 2015

Posted by **Mandi** on Friday, April 27, 2012 at 4:18am.

(a) How much energy is this in calories?

(b) What is the final temperature of the water?

I know that to find (a) I have to use the constant 4.19 J and divide it into the 500 J yielding 119.33 calories. How do I find final temperature?

- Physics -
**Elena**, Friday, April 27, 2012 at 7:55am1J =0.2388 cal

500 J = 119.4229 cal.

Q =mcΔT,

ΔT = Q/mc = 500/0.059•4180 =02.03 oC

T1 = 20+ 2.03 = 22.03 oC

**Answer this Question**

**Related Questions**

Science - 1. How much heat energy is lost by 3 kg of water when it cools from 80...

physics - 0.1kg of ice initially at a temperature of -10 degrees Celsius is ...

physics - If 1200 cal of heat are added to 50 g of water initially at a ...

physics - Assume that 10 g of steam is added to 100 g of water initially at 19°C...

physics - 1. Assume that 10 g of steam is added to 100 g of water initially at ...

physical science - If 500 kg of water at 200 degrees F is poured into a lake ...

Physics Heat - 1) While Laurie is boiling water to cook spaghetti, the phone ...

Physics 11th grade 'Heat' ` - 1) While Laurie is boiling water to cook spaghetti...

physics - A 40-g block of ice is cooled to −71°C and is then added to 590...

physics - A 40-g block of ice is cooled to −71°C and is then added to 590 ...