Posted by **Mandi** on Friday, April 27, 2012 at 4:18am.

500 J of heat are added to 59 g of water initially at 20°C.

(a) How much energy is this in calories?

(b) What is the final temperature of the water?

I know that to find (a) I have to use the constant 4.19 J and divide it into the 500 J yielding 119.33 calories. How do I find final temperature?

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