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September 2, 2014

September 2, 2014

Posted by **Romy** on Thursday, April 26, 2012 at 6:40pm.

(a) 1.0 m

min

(b) 10.0 m

min

Please someone help me out with this. Thank you!

physics someone please helpp - bobpursley, Wednesday, April 25, 2012 at 12:12pm

calculate the pressures at those depths.

Then, use the Boyle's law (constant temp).

Ptank*volumetank=pressuredepth*n*.4Liters

volume of the tank in liters is 10liters.

solve for n. On the pressure at depth, be certain to add atmospheric pressure which is on top of the water.

physics someone please helpp - Elena, Wednesday, April 25, 2012 at 3:33pm

p1•V1 = p2•V2

p2 = p1+ ρ•g•h1 + p(atm) = 10^7 +1000•9.8•1 + 101325 = 1.011•10^7 Pa,

V2 = p1•V1/p2 = 0.01•10^7/1.011•10^7 =9.89•10^-3 m^3

t = V2/Vo = 9.89•10^-3/0.4•10^-3 =24.7 s.

p1•V1 = p3•V3,

p2 = p1+ ρ•g•h2 + p(atm) = 10^7 +1000•9.8•10 + 101325 = 1.019•10^7 Pa,

V3 = p1•V1/p3 = 0.01•10^7/1.019•10^7 =9.81•10^-3 m^3

t = V3/Vo = 9.81•10^-3/0.4•10^-3 =24.5 s.

physics to Elena please reply - Romy, Wednesday, April 25, 2012 at 6:36pm

thanks Elena I really appreciate your help, but the answer has to be in minute and I got .42 min for 24.7 s, and .41 min for 24.5 s, but its wrong I don;t know why can you please help.

Thanks :)

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