Posted by Jess on Thursday, April 26, 2012 at 3:19pm.
I will assume you want the area to be
(1-x)/(x^2 +1)
area = l x w
so (1-x)/(x^2 + 1 ) = w(x-1)
w = [ (1-x)/(x^2 + 1) ] / (x-1)
= -1/(x^2 + 1)
What I would say is "There is no real number for the width"
-since x^2 is always positive, then x^2 + 1 is always positive
Thus -1/(a positive) = a negative
We cannot have a negative width
unless you want your typed version to have a different meaning besides my interpretation.
the way you typed it it would have a value of 2 - 1/x
and I am pretty sure you didn't mean that.
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