algebra2
posted by Chelsea:) .
A package with square ends has combined length and girth(girth is perimeter of a cross section) of 120 in. The surface area of the entire package is 3600 sq. in.
Determine the dimensions of the package.
s in. * s in.* l in.
One solution is: 11.08in. * 11.08in. * 75.68in. Find the other solution
Hint: if 4s+length=120 then length=1204S
Round your answer to 2 decimals. Enter the 3 dimensions separated by commas

looks like you defined s to be the measure of each of the sides of the end.
let the length be l
so girth = 4s + l = 120
total area = 2s^2 + 4 sl = 3600
s^2 + 2sl = 1800
s^2 + 2s(1204s)  1800 = 0
s^2 + 240s  8s^2  1800=0
7s^2  240s +1800 = 0
by the formula
s = (240 ± √7200)/14
s = 11.08 or s = 23.20
if s=23.20 , then l = 1204(23.20) = 27.18
23.20 , 23.20 , 27.18