What makes #Ag2S+2Al(s)=Al2S3+6Ag(s) ?
What makes 3Ag2S+2Al(s)=Al2S3+6Ag(s) ?
I don't understand the question.
The chemical equation you've provided represents a reaction between silver sulfide (Ag2S) and aluminum (Al) to form aluminum sulfide (Al2S3) and silver (Ag).
To understand why this reaction occurs, we need to consider the reactivity series of metals. The reactivity series arranges metals in order of their reactivity, with the most reactive metals at the top and the least reactive metals at the bottom. In this case, aluminum is more reactive than silver.
In the given reaction, aluminum is more reactive than silver. This means that aluminum has a greater tendency to lose electrons compared to silver. When aluminum reacts with silver sulfide (Ag2S), it displaces silver from the compound and forms aluminum sulfide (Al2S3) as a product. The displaced silver combines to form silver metal (Ag).
Let's examine the reaction step by step:
1. Ag2S (silver sulfide) is an ionic compound composed of silver cations (Ag+) and sulfide anions (S2-).
2. Aluminum (Al) is a more reactive metal than silver.
3. During the reaction, aluminum atoms (Al) replace the silver cations (Ag+) in silver sulfide (Ag2S), leading to the formation of aluminum sulfide (Al2S3).
- The aluminum atoms lose three electrons and are oxidized to form aluminum cations (Al3+).
- These aluminum cations combine with sulfide anions (S2-) from the silver sulfide (Ag2S) to form aluminum sulfide (Al2S3).
4. The displaced silver cations combine with each other to form silver metal (Ag), resulting in the production of six silver atoms (Ag) in the reaction.
Overall, this chemical reaction occurs because aluminum is more reactive than silver, which allows it to displace silver from silver sulfide to form aluminum sulfide and elemental silver.