Saturday

July 26, 2014

July 26, 2014

Posted by **Miso** on Wednesday, April 25, 2012 at 11:34pm.

a)- clearly explain how (why) he can get back to safety by throwing the object(s). Which direction should he throw them?

b)- how long (if ever) will take him to get back to the space station by throwing the hammer ?

c)- how long will it take him to get back if he throws away the hammer and the expensive antenna?

(neglect any time difference between throwing the two objects)

- Physics- momentum please helppp!!! -
**Elena**, Thursday, April 26, 2012 at 5:13pms =5 m, m = 95 kg, m1= 1 kg, m2 = 15 kg, v=0.1 m/s, v1 = 10 m/s, v2= 2 m/s.

1. Hammer

(m+m1+m2) •v = m1•v1 – (m+m2)•u1

u1 = {m1•v1 - (m+m1+m2) •v}/{m+m2} =

={1•10 –(95+1+15) •0.1}/{95+15} = - 0.01 m/s.

Astronaut will move in previous direction (away from the station)

but at smaller speed.

2. Antenna

(m+m1+m2) •v = m2•v2 – (m+m1)•u2,

u2 = {m1•v1 - (m+m1+m2) •v}/{m+m1} =

={15•2 –(95+1+15) •0.1}/{95+11} = 0.2 m/s.

t1= s/u2 = 5/0.2 = 25 s.

2. Hammer+Antenna

(m+m1+m2) •v = m1•v1+ m2•v2 – m•u3,

u3= {m1•v1+ m2•v2 - (m+m1+m2) •v}/m =

={1•10+15•2 –(95+1+15) •0.1}/95 = 0.3 m/s.

t2 = s/u3 = 5/0.3 = 16.7 s.

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