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November 23, 2014

November 23, 2014

Posted by **Anonymous** on Wednesday, April 25, 2012 at 10:04pm.

- Algebra: Parabolas -
**Steve**, Wednesday, April 25, 2012 at 11:59pmSince it's a standard

y^2 = ax, then we know that

16 = 3a

a = 16/3

which makes p = a/4 = 4/3

- Algebra: Parabolas -
**Anonymous**, Thursday, April 26, 2012 at 4:49amSo it doesn't matter what point is given as long as it's on the parabola?

- Algebra: Parabolas -
**Steve**, Thursday, April 26, 2012 at 10:40amThat's not quite true. They gave the added information that it's a standard parabola with the x-axis as its axis of symmetry, and (0,0) as its vertex.

In general, knowing only one point on the curve is not enough, but with what they said, you know that you also have (0,0) and (3,-4) as points on the curve.

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