Posted by Anonymous on Wednesday, April 25, 2012 at 10:04pm.
Since it's a standard
y^2 = ax, then we know that
16 = 3a
a = 16/3
which makes p = a/4 = 4/3
So it doesn't matter what point is given as long as it's on the parabola?
That's not quite true. They gave the added information that it's a standard parabola with the x-axis as its axis of symmetry, and (0,0) as its vertex.
In general, knowing only one point on the curve is not enough, but with what they said, you know that you also have (0,0) and (3,-4) as points on the curve.
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