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April 25, 2014

April 25, 2014

Posted by **BARBARA** on Wednesday, April 25, 2012 at 9:55pm.

FIND THE DIMENSIONS OF THE SIGN

WHAT IS THE LENGTH

WHAT IS THE WIDTH

- COLLEGE ?? ALGEBRA -
**Ms. Sue**, Wednesday, April 25, 2012 at 9:56pmWhat is the shape of the sign?

- COLLEGE ALGEBRA -
**Anonymous**, Wednesday, April 25, 2012 at 10:14pmAssuming the sign is rectangular, your initial formula is

P = 2L + 2W

You know the perimeter is 78 inches so replace P with 78.

78 = 2L + 2W

You know that the length is 7 inches longer than the width.

78 = 2(W + 7) + 2W

Simplify.

78 = 2W + 14 +2W

78 = 4W + 14

Solve for W, the width.

64 = 4W

16 = W

Add 7 to find the length.

16 + 7 = L

23 = L

The length is 23 inches. The width is 16 inches.

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