Posted by **BARBARA** on Wednesday, April 25, 2012 at 9:55pm.

THE PRIMETER OF SOME TRAFFIC SIGN MUST BE 78INCHES ALSO ITS LENGTH IS 7INCHES LONGER THAN ITS WIDTH

FIND THE DIMENSIONS OF THE SIGN

WHAT IS THE LENGTH

WHAT IS THE WIDTH

- COLLEGE ?? ALGEBRA -
**Ms. Sue**, Wednesday, April 25, 2012 at 9:56pm
What is the shape of the sign?

- COLLEGE ALGEBRA -
**Anonymous**, Wednesday, April 25, 2012 at 10:14pm
Assuming the sign is rectangular, your initial formula is

P = 2L + 2W

You know the perimeter is 78 inches so replace P with 78.

78 = 2L + 2W

You know that the length is 7 inches longer than the width.

78 = 2(W + 7) + 2W

Simplify.

78 = 2W + 14 +2W

78 = 4W + 14

Solve for W, the width.

64 = 4W

16 = W

Add 7 to find the length.

16 + 7 = L

23 = L

The length is 23 inches. The width is 16 inches.

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