Posted by **Jay** on Wednesday, April 25, 2012 at 7:01pm.

Square root of (q^2+7q+6) minus q minus 3=0. Minus 3 and minus q are not under he radical sign.

- Algebra -
**MathGuru**, Thursday, April 26, 2012 at 7:16pm
I assume your problem is this:

√(q^2 + 7

- Algebra -
**MathGuru**, Thursday, April 26, 2012 at 7:25pm
Oops! Let's try this again.

I assume your problem is this:

√(q^2 + 7q + 6) - q - 3 = 0

Add q and 3 to both sides of the equation to get the radical by itself (whatever operation you do to one side of an equation you must do to the other side as well):

√(q^2 + 7q + 6) = q + 3

Now square both sides to get rid of the radical:

q^2 + 7q + 6 = (q + 3)^2

q^2 + 7q + 6 = q^2 + 6q + 9

q = 3

Test the answer with the original equation to see if it checks out. It always helps to check your work!

I hope this helps and is what you were asking.

## Answer this Question

## Related Questions

- math - Here's my question: Determine if each system has one, two, or no ...
- algebra,math - Solve the equation. 4 times the square root of x minus 5 minus 8...
- Calc - Find the functions a) f o g, b) g o f, c) f o f, d) g o g, and their ...
- Calculus - Find the functions a) f o g, b) g o f, c) f o f, d) g o g, and their ...
- Math - Simplify 5 square root of 7 end root plus 12 square root of 6 end root ...
- Algebra - I am a bit confused about conjugates in algebra. I am supposed to ...
- Algebra (urgent!) - I am a bit confused about conjugates in algebra. I am ...
- chem/stats - Find the absolute error for the answer of the following equation: ...
- Algebra help - Solve by completing the square x2 - 2x - 5 = 0. Help please a)1 ...
- math - 1.0 Four square root of seven open bracket two square root of three plus ...

More Related Questions