Posted by **Shelley ** on Wednesday, April 25, 2012 at 5:34pm.

The three station work cell illustrated in Figure S7.7, has a product that must go through one of the two machines at station 1 (they are parallel) before proceeding to station 2.

Station 1-Machine A-Capacity: 20 units/hr

Station 2-Capacity: 5 units/

Station 3-Capacity: 12 units/hr

a). What is the process of the system?

B) What is the bottleneck time of this week cell?

c) What is the process cycle time?

D) If the firm operates 10 hours per day, 5 days per weekl, what is the weekly capacity of this work cell?

Station 1-Machine B-Capacity: 20 units/hrs

- Operations Management 10th edition -
**Sally Field**, Thursday, November 15, 2012 at 6:17am
a) What is the process time of the system?

Since the product must go through one of the two machines at Station 1 before proceeding to Station 2, the process time of the system is 20 units per hour. Therefore, either Machine A or Machine B represents the process time of each assembly line.

b) What is the bottleneck time of this work cell?

The bottleneck time of this work cell is Station 2, which has a capacity of 5 units per hour. This becomes the bottleneck for the entire product because Station 1 can product 20 units per hour and if they both send to Station 2, that would be 40 units per hour. This would cause a delay or bottleneck because Station 2 is only able to produce or accommodate 5 units per hour.

c) What is the process cycle time?

The process cycle time is 20 units + 5 units + 12 units (total of 37 units per hour)

d) If the firm operates 10 hours per day, 5 days per week, what is the weekly capacity of this work cell?

10 hours per day

5 days per week

37 units per hour X 10 hours per day = 370 units per day

370 units per day X 5 days = 1,850 units per week

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