Mr. Rainier's car uses about 1.6 fluid ounces of gas per minute when the engine is idling. One night, he parked his car but forgot to turn off the motor. He had just filled his tank. His tank holds 12 gallons.

About how many hours will it take before his car runs out of gas?

1 gallon = 128 fluid ounces

1 hour = 60 minutes

Let x = time in hours.

(1.6)(60)x = 12(128)

Solve for x.

To find out how many hours it will take before Mr. Rainier's car runs out of gas, we first need to convert the given fuel consumption rate of 1.6 fluid ounces per minute into gallons per hour.

Since there are 128 fluid ounces in a gallon, we can calculate the fuel consumption rate in gallons per hour as follows:

1.6 fluid ounces/minute * 60 minutes/hour * (1 gallon/128 fluid ounces) = 0.075 gallons/hour

Now we can calculate the time it will take for the car to run out of gas by dividing the total gas tank capacity (12 gallons) by the fuel consumption rate (0.075 gallons/hour):

12 gallons / 0.075 gallons/hour ≈ 160 hours

Therefore, it will take approximately 160 hours before Mr. Rainier's car runs out of gas if the engine remains idling.