Posted by Jenna on Wednesday, April 25, 2012 at 2:31pm.
(6x2y)/(x^2+xy2y^2)(3x+2y)/(x^2+3xy4y^2)

algebra  Steve, Wednesday, April 25, 2012 at 4:05pm
x^2+xy2y^2 = (x+2y)(xy)
x^2+3xy4y^2 = (x+4y)(xy)
so, the LCD = (x+2y)(x+4y)(xy) and putting it all over that LCD, the numerator then becomes
(6x2y)(x+4y)  (3x+2y)(x+2y)
= 6x^2 +22xy  8y^2
 3x^2 +8xy + 4y^2
= 3x^2 + 14xy  12y^2
so, the final fraction is
3x^2 + 14xy  12y^2

(x+2y)(x+4y)(xy)
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