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April 19, 2015

April 19, 2015

Posted by **matin** on Wednesday, April 25, 2012 at 12:07pm.

- physics -
**Henry**, Thursday, April 26, 2012 at 10:09pmVo = 105 m/s @ 37 Deg.

Xo = hor. = 105*cos37 = 83.9 m/s.

Yo = ver. = 105*sin37 = 63.2 m/s.

h = ho + (Y^2-Yo^2)/2g.

h = 125 + (0-(63.2)^2) / -19.6=328.8 m

above gnd.

Tr = (Y-Yo)/g=(0-63.2) / -9.8=6.45 s.

= Rise time.

a. h = Vo*t + 4.9t^2 = 328.8 m.

0 + 4.9t^2 = 328.8.

t^2 = 328.8 / 4.9 = 67.1.

Tf = 8.19 s. = Fall time.

b. Range=Xo*(Tr+Tf)=83.9(6.45+8.19)=1228.3 m.

c. Y = Yo + gt.

Y = ver. = 0 + 9.8*8.19 = 80.3 m/s.

X = hor = Xo = 83.9 m/s.

d. V = sqrt(X^2+Y^2).

V = sqrt((83.9)^2+(80.3)^2) = 116 m/s.

e. tanA = Y/X = 80.3 / 83.9 = 0.95709.

A = 43.7 Deg.

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