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March 29, 2015

March 29, 2015

Posted by **Anonymous** on Wednesday, April 25, 2012 at 11:27am.

- pre- cal -
**Steve**, Wednesday, April 25, 2012 at 12:09pmAs usual, draw a diagram.

Draw a horizontal line from the base of the wire to the base of the tower. (It will lie underground, but give you a right triangle to work with.)

If we label

T = top of tower

W = base of wire

B = base of tower

P = the point below the base of the tower where the horizontal line from B intersects.

Let u = BP

v = WP

u = 50sin5° = 4.36

v = 50cos5° = 49.81

wire length = √(v^2+(25+u)^2)

= √(49.81^2 + 29.36^2)

= 57.82

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