Posted by **Amber** on Wednesday, April 25, 2012 at 12:19am.

A force F=Fx ˆi + Fy ˆj + Fz ˆk acts on a particle located at X= (x, y, z). Given Fx=−88.3N, Fy=7.56N, Fz=60N, x= −3.65m, y=1.67m and z=7.03m,

calculate the three components of the torque vector ~ = xˆi + y ˆj + z ˆk .

First, calculate the x component.

Answer in units of Nm

- Physics. PLEASE HELP!! -
**Damon**, Wednesday, April 25, 2012 at 2:00am
torque about origin

M = R cross F

i j k

x y z

Fx Fy Fz determinant

=(y Fz-z Fy)i+(z Fx-x Fz)j *(x Fy-y Fx)k

so x component

(y Fz-z Fy)

= 1.67*60 - 7.03*7.56

= 47.1 Nm

- Physics. PLEASE HELP!! -
**Amber**, Wednesday, April 25, 2012 at 11:51am
How do you calculate the y component.

Answer in units of Nm.

How do you calculate the z component.

Answer in units of Nm.

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