Physics. PLEASE HELP!!
posted by Amber .
A force F=Fx ˆi + Fy ˆj + Fz ˆk acts on a particle located at X= (x, y, z). Given Fx=−88.3N, Fy=7.56N, Fz=60N, x= −3.65m, y=1.67m and z=7.03m,
calculate the three components of the torque vector ~ = xˆi + y ˆj + z ˆk .
First, calculate the x component.
Answer in units of Nm

torque about origin
M = R cross F
i j k
x y z
Fx Fy Fz determinant
=(y Fzz Fy)i+(z Fxx Fz)j *(x Fyy Fx)k
so x component
(y Fzz Fy)
= 1.67*60  7.03*7.56
= 47.1 Nm 
How do you calculate the y component.
Answer in units of Nm.
How do you calculate the z component.
Answer in units of Nm.