Posted by Amber on Wednesday, April 25, 2012 at 12:19am.
A force F=Fx ˆi + Fy ˆj + Fz ˆk acts on a particle located at X= (x, y, z). Given Fx=−88.3N, Fy=7.56N, Fz=60N, x= −3.65m, y=1.67m and z=7.03m,
calculate the three components of the torque vector ~ = xˆi + y ˆj + z ˆk .
First, calculate the x component.
Answer in units of Nm

Physics. PLEASE HELP!!  Damon, Wednesday, April 25, 2012 at 2:00am
torque about origin
M = R cross F
i j k
x y z
Fx Fy Fz determinant
=(y Fzz Fy)i+(z Fxx Fz)j *(x Fyy Fx)k
so x component
(y Fzz Fy)
= 1.67*60  7.03*7.56
= 47.1 Nm

Physics. PLEASE HELP!!  Amber, Wednesday, April 25, 2012 at 11:51am
How do you calculate the y component.
Answer in units of Nm.
How do you calculate the z component.
Answer in units of Nm.
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