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Physics. PLEASE HELP!!

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A force F=Fx ˆi + Fy ˆj + Fz ˆk acts on a particle located at X= (x, y, z). Given Fx=−88.3N, Fy=7.56N, Fz=60N, x= −3.65m, y=1.67m and z=7.03m,
calculate the three components of the torque vector ~ = xˆi + y ˆj + z ˆk .
First, calculate the x component.
Answer in units of Nm

  • Physics. PLEASE HELP!! -

    torque about origin

    M = R cross F

    i j k
    x y z
    Fx Fy Fz determinant

    =(y Fz-z Fy)i+(z Fx-x Fz)j *(x Fy-y Fx)k

    so x component
    (y Fz-z Fy)
    = 1.67*60 - 7.03*7.56
    = 47.1 Nm

  • Physics. PLEASE HELP!! -

    How do you calculate the y component.
    Answer in units of Nm.
    How do you calculate the z component.
    Answer in units of Nm.

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