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A solution contains 1.72 10-3 M Ca(NO3)2.

Determine the mass of the Ca2+ ions in 1.8 mL of this solution.

How many nitrate ions are there in 3.0 10-6 L (3.0 ┬ÁL) of this solution?

(i keep doing these two wrong but not sure why)

  • chemistry -

    It would have helped if you showed your work. That way I could see if there is an error in how you view the concept.
    mols Ca(NO3)2 = M x L = ?
    mass Ca^2+ = mols x atomic mass Ca.

    moles Ca(NO3)2 = M x L = ?
    mols NO3^- = twice that. Then 1 mol NO3^- = 6.02E23 ions. Convert from that.

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