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September 2, 2014

September 2, 2014

Posted by **kacey** on Tuesday, April 24, 2012 at 8:45pm.

solve for x.

please help me with this one and show the work so i can understand

- math -
**muhammad**, Wednesday, April 25, 2012 at 4:27amdivide both sides of equation by 9

x-5=4x-5

or

4x-5=x-5

add 5 and -x on both sides

4x-5-x+5=x-5-x+5

3x=0

divide both sides by 3

3x/3=0/3

x=0

- math - Correction -
**Steve**, Wednesday, April 25, 2012 at 10:58amThe instructions were correct, but the execution went awry:

divide**both**sides by 9

x-5 = (4x-5)/9 = 4x/9 - 5/9

add 5 - 4x/9 to both sides

x - 4x/9 = 5 - 5/9

5x/9 = 40/9

x = 8

final step -- check your answer:

x=0 does not work.

9(8-5) = 27 = 32-5

- math -
**visoth**, Friday, April 27, 2012 at 1:32amif i may say it would probably be easier and less complicated if you had follow PEMDAS instruction which tells you to take the equation on the left 9(x-5) and multiply it out first instead of dividing the two equation by 9. that way you get 9x-45=4x-5, subtract 4x from both side so you get 5x-45=-5 and then add 45 to both side to get 9x=40 and then divide by 9 so that you get x on it own to get 40/9 and you messed up the math a little near the endx-4x/9 wouldnt have given you 5x/9

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