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January 30, 2015

January 30, 2015

Posted by **Lee** on Tuesday, April 24, 2012 at 7:31pm.

Problem: 4+2i/4-2i

- Algebra -
**Damon**, Tuesday, April 24, 2012 at 7:45pmi = sqrt (-1)

so i^2 = sqrt (-1)(sqrt(-1) = -1

(4+2i)/(4-2i)

to get rid of i in the denominator multiply top and bottom by the "comlex conjugate of (4-2i) which is (4+2i)

Rule: conjugate of (a-bi) is (a+bi)

(4+2i)(4+2i)

-------------

(4-2i)(4+2i)

16 + 16 i +4 i^2

=-------------------

(16 - 2 i^2)

but we all know that i^2 = -1 so

12 + 16 i

----------

18

or

6 + 8 i

--------

9

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