Calculate the magnitude of the force between two 3.95 µC point charges 7.4 cm apart
Nothing to be lost about.
Coulombs Law: force=kQ1*Q2/distance^2
I can check your work. Work this in the SI system of units.
What is Q2 though?
Q1=Q2=3.95microC
Nevermind i read that wrong
Thank you so much, i got it right
To calculate the magnitude of the force between two point charges, you can use Coulomb's Law. Coulomb's Law states that the magnitude of the electrostatic force between two point charges is equal to the product of the charges, divided by the square of the distance between them, and multiplied by a constant called the electrostatic constant.
The formula for Coulomb's Law is:
F = (k * |q1 * q2|) / r^2
Where:
F is the magnitude of the electrostatic force
k is the electrostatic constant, which has a value of approximately 9 × 10^9 N·m^2/C^2
|q1| and |q2| are the magnitudes of the charges of the two point charges
r is the distance between the two point charges
In this case, the magnitudes of the charges are given as 3.95 µC, which is equivalent to 3.95 × 10^-6 C. The distance between the charges is given as 7.4 cm, which is equivalent to 0.074 m.
Plugging these values into the formula, we get:
F = (9 × 10^9 N·m^2/C^2 * |3.95 × 10^-6 C * 3.95 × 10^-6 C|) / (0.074 m)^2
Simplifying this equation gives:
F = (9 × 10^9 N·m^2/C^2 * (3.95 × 10^-6 C)^2) / (0.074 m)^2
Calculating this expression will give you the magnitude of the force between the two point charges.