Posted by What's the Difference? on Tuesday, April 24, 2012 at 5:39pm.
do the ratio test:
ratio (An+1)/An=
the series is SUM (1/n)^5 for n=1>inf
ratio [(1/n+1)/ (1/n)]^5=(n/(n+1))^5 which is less than 1, so the series converges. This means, if you add all the terms, the sum will be a finite q
do the ratio test:
ratio (An+1)/An=
the series is SUM (1/n)^5 for n=1>inf
ratio [(1/n+1)/ (1/n)]^5=(n/(n+1))^5 which is less than 1, so the series converges. This means, if you add all the terms, the sum will be a finite quanity. If the ratio had been 1 or greater, the series would have been divergent.
http://abacus.bates.edu/acad/acad_support/msw/convergence_tests.pdf
Related Questions
calculus - Use the ratio test to determine whether the series is convergent or ...
calculus - use the comparison test to determine whether the series is ...
calculus - is this correct? use the integral test to determine if this series is...
Pre-calculus - Which of the following series is divergent? a) 1+3(1/4)+9(1/4)^2+...
calculus - use the integral test to determine whether the series is convergent ...
calculus - Use the ratio test to determine whether each series is convergent or ...
Calculus - I was able to solve (e), this is the only one I don't get. ...
calculus (integral test) - use integral test to determine whether the series is ...
calculus - The sum from 0 to infinity of (-1)^n(3/3^n) is convergent or ...
calculus - Determine whether the series is convergent o divergent and say what ...
For Further Reading