Posted by
**Anonymous** on
.

Use this reaction to answer the question: 2KClO3 -> 2KCl + 3O2

If I start with 65g KClO3, how many mol O2 will be formed? How many g O2?

If I need to produce 299g KCl, how many mol of KClO3 do I need to start with? How many g KClO3?