Posted by Lueshelle on .
Factor using the AC method..6x^34x^210x

intermediate algebra 
bobpursley,
first factor out an x.
2x(3x^22x5)
Now you have a quadratic in the form of
(ax^2+bx+c)
2x(3x5)(x+1)
Posted by Lueshelle on .
Factor using the AC method..6x^34x^210x
first factor out an x.
2x(3x^22x5)
Now you have a quadratic in the form of
(ax^2+bx+c)
2x(3x5)(x+1)